Step 1 :Write the following expression in expanded form: \(\ln [x(x-1)]\)
Step 2 :The natural logarithm, ln, has a property that allows the logarithm of a product to be written as the sum of the logarithms of the individual factors.
Step 3 :In this case, the expression inside the logarithm, x(x-1), is a product of x and (x-1). Therefore, we can use the property of logarithms to write this as the sum of the logarithms of x and (x-1).
Step 4 :Final Answer: \(\boxed{\ln [x(x-1)]= \ln x + \ln (x-1)}\)