A can of soda is placed inside a cooler. As the soda cools, its temperature $T(x)$ in degrees Celsius is given by the following function, where $x$ is the number of minutes since the can was placed in the cooler. \[ T(x)=-5+25 e^{-0.04 x} \] Find the temperature of the soda after 10 minutes and after 20 minutes. Round your answers to the nearest degree as necessary.

Step 1 ：The temperature of the soda after a certain number of minutes is given by the function \(T(x)=-5+25 e^{-0.04 x}\), where \(x\) is the number of minutes since the can was placed in the cooler.

Step 2 ：To find the temperature of the soda after 10 minutes, we substitute \(x=10\) into the function to get \(T(10)=-5+25 e^{-0.04 \times 10}\).

Step 3 ：Calculating this gives \(T(10)\approx 12\) degrees Celsius.

Step 4 ：To find the temperature of the soda after 20 minutes, we substitute \(x=20\) into the function to get \(T(20)=-5+25 e^{-0.04 \times 20}\).

Step 5 ：Calculating this gives \(T(20)\approx 6\) degrees Celsius.

Step 6 ：Final Answer: The temperature of the soda after 10 minutes is \(\boxed{12}\) degrees Celsius and after 20 minutes is \(\boxed{6}\) degrees Celsius.