\begin{tabular}{|c|c|} \hline$x$ & $y$ \\ \hline-2 & 4 \\ \hline 1 & 2.5 \\ \hline 5 & \\ \hline 10 & -2 \\ \hline \end{tabular} The variables $x$ and $y$ in the table above are in a linear relationship that is NOT NECESSARILY PROPORTIONAL What is the value of $y$ when $x$ is 5 ? \[ \begin{array}{l} y=-10 \\ y=0.5 \\ y=-1.5 \\ y=1 \\ y=1.5 \end{array} \]

Step 1 ：The variables $x$ and $y$ in the table are in a linear relationship that is not necessarily proportional. The relationship can be represented by the equation $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept.

Step 2 ：We can find the values of $m$ and $b$ by using the two points given in the table (-2, 4) and (1, 2.5).

Step 3 ：Using these points, we find that $y = 0.49999999999999734$.

Step 4 ：We are asked to find the value of $y$ when $x$ is 5. Substituting $x = 5$ into the equation, we find that $y$ is approximately 0.5.

Step 5 ：However, since the options are all integers or half integers, we can round this to the nearest half integer, which is 0.5.

Step 6 ：Final Answer: \(\boxed{0.5}\)