Step 1 :State the null and alternative hypothesis. The null hypothesis is that the reading rate is equal to 198 wpm, and the alternative hypothesis is that the reading rate is greater than 198 wpm.
Step 2 :Calculate the test statistic and the p-value. The test statistic is calculated as the difference between the sample mean and the hypothesized population mean, divided by the standard error of the sample mean. The p-value is the probability of observing a test statistic as extreme as, or more extreme than, the observed test statistic, under the null hypothesis.
Step 3 :Compare the p-value to the level of significance. If the p-value is less than the level of significance, we reject the null hypothesis and conclude that the reading rate is greater than 198 wpm. If the p-value is greater than the level of significance, we do not reject the null hypothesis and conclude that the reading rate is equal to 198 wpm.
Step 4 :The test statistic is approximately \(\boxed{3.5049}\) and the p-value is approximately \(\boxed{0.0033}\). Since the p-value is less than the level of significance (0.05), we reject the null hypothesis.
Step 5 :Therefore, there is evidence at the 0.05 level of significance to conclude that your friend's reading rate is greater than 198 wpm.
Step 6 :Final Answer: Null hypothesis: The reading rate is equal to 198 wpm. Alternative hypothesis: The reading rate is greater than 198 wpm. Test statistic: \(\boxed{3.5049}\) P-value: \(\boxed{0.0033}\) Conclusion: There is evidence at the 0.05 level of significance to conclude that your friend's reading rate is \(\boxed{\text{greater than}}\) 198 wpm.