Problem

Solve the system by elimination. First, clear the denominators. \[ \begin{array}{r} \frac{5 x}{2}+\frac{5 y}{3}=\frac{40}{3} \\ \frac{x}{4}+\frac{y}{3}=\frac{13}{6} \end{array} \]

Solution

Step 1 :Given the system of equations: \[\frac{5 x}{2}+\frac{5 y}{3}=\frac{40}{3}\] and \[\frac{x}{4}+\frac{y}{3}=\frac{13}{6}\]

Step 2 :First, we clear the denominators by multiplying each equation by the least common multiple (LCM) of the denominators. The LCM of 2, 3, 4, and 6 is 12.

Step 3 :After clearing the denominators, the equations become: \[30x + 20y = 160\] and \[3x + 4y = 26\]

Step 4 :Next, we use the elimination method to solve the system of equations.

Step 5 :By solving the system, we find that the solution is \(x = 2\) and \(y = 5\)

Step 6 :Final Answer: The solution to the system of equations is \(\boxed{x = 2, y = 5}\)

From Solvely APP
Source: https://solvelyapp.com/problems/20305/

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