Solve the system by substitution. \[ \begin{array}{l} 4 x-y=-10 \\ 2 y-x=13 \end{array} \]

Step 1 ：Given the system of equations: \[\begin{array}{l} 4x - y = -10 \ 2y - x = 13 \end{array}\]

Step 2 ：Express one variable in terms of the other from one equation. From the first equation, we can express y in terms of x: \[y = 4x + 10\]

Step 3 ：Substitute this expression into the other equation. This gives us: \[ -x + 2(4x + 10) = 13 \] which simplifies to \[7x + 20 = 13\]

Step 4 ：Solve this equation for x. Subtracting 20 from both sides gives \[7x = -7\] Dividing both sides by 7 gives \[x = -1\]

Step 5 ：Substitute x = -1 back into the first equation to find the value of y: \[4(-1) - y = -10\] which simplifies to \[-4 - y = -10\] Adding 4 to both sides gives \[-y = -6\] Multiplying both sides by -1 gives \[y = 6\]

Step 6 ：Final Answer: The solution to the system of equations is \(\boxed{x = -1, y = 6}\)