Determine the point estimate of the population proportion, the margin of error for the following confidence interval, and the number of individuals in the sample with the specified characteristic, $x$, for the sample size provided. Lower bound $=0.361$, upper bound $=0.699, n=1200$ The point estimate of the population proportion is 0.53 . (Round to the nearest thousandth as needed.) The margin of error is (Round to the nearest thousandth as needed.)

Step 1 ：The point estimate of the population proportion is the midpoint of the confidence interval, which can be calculated as the average of the lower and upper bounds. In this case, the lower bound is 0.361 and the upper bound is 0.699. So, the point estimate is \(\frac{0.361 + 0.699}{2} = 0.53\).

Step 2 ：The margin of error is the difference between the point estimate and either the lower or upper bound of the confidence interval. In this case, the point estimate is 0.53 and the lower bound is 0.361. So, the margin of error is \(0.53 - 0.361 = 0.169\).

Step 3 ：The number of individuals in the sample with the specified characteristic, $x$, can be calculated by multiplying the point estimate by the sample size, $n$. In this case, the point estimate is 0.53 and the sample size is 1200. So, $x$ is \(0.53 \times 1200 = 636\).

Step 4 ：Final Answer: The point estimate of the population proportion is \(\boxed{0.53}\). The margin of error is \(\boxed{0.169}\). The number of individuals in the sample with the specified characteristic, $x$, is \(\boxed{636}\).