Problem
Determine the point estimate of the population proportion, the margin of error for the following confidence interval, and the number of individuals in the sample with the specified characteristic, $x$, for the sample size provided. \[ \text { Lower bound }=0.361 \text {, upper bound }=0.699, n=1200 \] The point estimate of the population proportion is (Round to the nearest thousandth as needed.)
Solution
Step 1 ：The point estimate of the population proportion is the midpoint of the confidence interval. This can be calculated by taking the average of the lower and upper bounds of the confidence interval.
Step 2 ：Given lower bound = 0.361 and upper bound = 0.699
Step 3 ：Calculate the point estimate as \((0.361 + 0.699) / 2 = 0.53\)
Step 4 ：Final Answer: The point estimate of the population proportion is \(\boxed{0.53}\)
