Step 1 :Given that the sample size n = 75, the population size N = 25000, and the population proportion p = 0.6.
Step 2 :First, we need to check if the sample size is less than or equal to 5% of the population size. This is a condition for the sampling distribution of the sample proportion to be approximately normal.
Step 3 :Calculate 5% of the population size: \(0.05 \times 25000 = 1250\). Since 75 is less than 1250, the condition is satisfied.
Step 4 :Next, we need to check if the expected number of successes and failures are both at least 10. This is another condition for the sampling distribution to be approximately normal.
Step 5 :Calculate the expected number of successes: \(n \times p = 75 \times 0.6 = 45\) and the expected number of failures: \(n \times (1-p) = 75 \times 0.4 = 30\). Since both are greater than 10, the condition is satisfied.
Step 6 :Therefore, the sampling distribution of the sample proportion is approximately normal.
Step 7 :Finally, we need to find the mean of the sampling distribution of the sample proportion. The mean is equal to the population proportion p.
Step 8 :So, the mean of the sampling distribution of the sample proportion is \(\boxed{0.6}\).
Step 9 :In conclusion, the best description for the shape of the sampling distribution is 'Approximately normal because n is less than or equal to 5% of N and np(1-p) is greater than 10'. The mean of the sampling distribution of the sample proportion is 0.6.