Factor the trinomial $9 x^{2}-36 x+36$ \[ 9 x^{2}-36 x+36=(A x-B)^{2} \] where $A$ is 3 and $B$ is

Step 1 ：Given the trinomial $9 x^{2}-36 x+36$

Step 2 ：We can see that this trinomial is a perfect square trinomial. The form of a perfect square trinomial is $(Ax-B)^2 = A^2x^2 - 2ABx + B^2$

Step 3 ：We can compare this with the given trinomial to find the values of A and B

Step 4 ：From the trinomial, we have a = 9, b = -36, c = 36

Step 5 ：Comparing with the form of a perfect square trinomial, we find A = 3.0 and B = 6.0

Step 6 ：Substituting the values of A and B into the form $(Ax-B)^2$, we get the factored form of the trinomial

Step 7 ：\(\boxed{(3x - 6)^2}\) is the factored form of the trinomial $9x^2 - 36x + 36$