olve the following inequality. \[ 2 x^{\frac{2}{3}} \leq-4 \] All real numbers. $-2.828 \leq x \leq 2.828$ There is no solution. $x \leq-2.828$ or $x \geq 2.828$

Step 1 ：The inequality is \(2x^{2/3} \leq -4\).

Step 2 ：Isolate \(x^{2/3}\) by dividing both sides by 2 to get \(x^{2/3} \leq -2\).

Step 3 ：Since \(x^{2/3}\) is always non-negative for real \(x\), it cannot be less than or equal to -2.

Step 4 ：Therefore, there is no solution to this inequality.

Step 5 ：Final Answer: \(\boxed{\text{No Solution}}\)