Step 1 :We are given that the weights of males are normally distributed with a mean of 187 pounds and a standard deviation of 39 pounds.
Step 2 :We are asked to find the probability that 1 randomly selected adult male has a weight greater than 142 pounds.
Step 3 :We can use the z-score formula to find the z-score for a weight of 142 pounds. The z-score formula is \(Z = \frac{X - \mu}{\sigma}\), where \(X\) is the value we are interested in, \(\mu\) is the mean, and \(\sigma\) is the standard deviation.
Step 4 :Substituting the given values into the z-score formula, we get \(Z = \frac{142 - 187}{39} = -1.1538461538461537\).
Step 5 :We then use a z-table or a statistical function to find the probability that a randomly selected male has a weight greater than 142 pounds. The probability corresponding to a z-score of -1.1538461538461537 is approximately 0.8757.
Step 6 :\(\boxed{0.8757}\) is the probability that 1 randomly selected adult male has a weight greater than 142 pounds.