Find the roots of the quadratic equation \(2x^2 - 5x + 2 = 0\)

Step 1 ：The quadratic formula is defined as \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)

Step 2 ：Substitute \(a = 2\), \(b = -5\), and \(c = 2\) into the formula

Step 3 ：Calculate \(x = \frac{-(-5) \pm \sqrt{(-5)^2 - 4*2*2}}{2*2}\)

Step 4 ：Simplify to obtain \(x = \frac{5 \pm \sqrt{25 - 16}}{4}\)

Step 5 ：Further simplify to obtain \(x = \frac{5 \pm \sqrt{9}}{4}\)

Step 6 ：Finally, you get \(x = \frac{5 \pm 3}{4}\)