Step 1 :An antiderivative of \(x^{n}\), as long as \(n \neq-1\), is \(\frac{x^{n+1}}{n+1}\).
Step 2 :In this case, the function is \(x^{7/8}\), so we can apply this rule directly.
Step 3 :The antiderivative of \(x^{7/8}\) is \(0.533333333333333*x^{1.875}\).
Step 4 :We will then evaluate the antiderivative at the upper limit of integration (1) and subtract the value of the antiderivative at the lower limit of integration (0).
Step 5 :The value of the integral \(\int_{0}^{1} x^{7 / 8} d x\) is \(\boxed{0.533333333333333}\).