Problem

Flying against the jetstream, a jet travels 6300 miles in 7 hours. Flying with the jetstream, the same jet travels 10,880 miles in 8 hours. What is the rate of the jet in still air and what is the rate of the jetstream? Note that the ALEKS graphing calculator can be used to make computations easier. Rate of the jet in still air: Rate of the jetstream: $\square \frac{\mathrm{mi}}{\mathrm{h}}$

Solution

Step 1 :Let's denote the rate of the jet in still air as 'j' and the rate of the jetstream as 's'.

Step 2 :When the jet is flying against the jetstream, the effective speed of the jet is (j - s) and it covers 6300 miles in 7 hours. So, we can write the equation as: \(7(j - s) = 6300\).

Step 3 :When the jet is flying with the jetstream, the effective speed of the jet is (j + s) and it covers 10880 miles in 8 hours. So, we can write the second equation as: \(8(j + s) = 10880\).

Step 4 :We can solve this system of equations to find the values of 'j' and 's'.

Step 5 :The solution to the system of equations is {j: 1130, s: 230}.

Step 6 :Final Answer: The rate of the jet in still air is \(\boxed{1130 \frac{\mathrm{mi}}{\mathrm{h}}}\) and the rate of the jetstream is \(\boxed{230 \frac{\mathrm{mi}}{\mathrm{h}}}\).

From Solvely APP
Source: https://solvelyapp.com/problems/19850/

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