Step 1 :Let's denote the rate of the jet in still air as 'j' and the rate of the jetstream as 's'.
Step 2 :When the jet is flying against the jetstream, the effective speed of the jet is (j - s) and it covers 6300 miles in 7 hours. So, we can write the equation as: \(7(j - s) = 6300\).
Step 3 :When the jet is flying with the jetstream, the effective speed of the jet is (j + s) and it covers 10880 miles in 8 hours. So, we can write the second equation as: \(8(j + s) = 10880\).
Step 4 :We can solve this system of equations to find the values of 'j' and 's'.
Step 5 :The solution to the system of equations is {j: 1130, s: 230}.
Step 6 :Final Answer: The rate of the jet in still air is \(\boxed{1130 \frac{\mathrm{mi}}{\mathrm{h}}}\) and the rate of the jetstream is \(\boxed{230 \frac{\mathrm{mi}}{\mathrm{h}}}\).