Step 1 :Given the integral \(\int x^{2} \sqrt{x^{3}+13} dx\) and the substitution \(u=x^{3}+13\).
Step 2 :Differentiate \(u\) with respect to \(x\) to get \(du\), \(du = 3x^{2} dx\).
Step 3 :Rearrange the equation to solve for \(dx\), \(dx = \frac{du}{3x^{2}}\).
Step 4 :Substitute \(u\) and \(dx\) into the integral, \(\int x^{2} \sqrt{u} \frac{du}{3x^{2}}\).
Step 5 :Simplify the integral to \(\frac{1}{3} \int \sqrt{u} du\).
Step 6 :Evaluate the integral, \(\frac{1}{3} \frac{2}{3} u^{\frac{3}{2}} + C\).
Step 7 :Substitute \(u\) back into the equation, \(\frac{2}{9} (x^{3}+13)^{\frac{3}{2}} + C\).
Step 8 :So, the solution to the integral is \(\boxed{\frac{2}{9} (x^{3}+13)^{\frac{3}{2}} + C}\).