Suppose $H(x)=(5-7 x)^{5}$. Find two functions $f$ and $g$ such that $(f \circ g)(x)=H(x)$. Neither function can be the identity function. (There may be more than one correct answer.) \[ \begin{array}{l} f(x)= \\ g(x)= \end{array} \]

Step 1 ：We need to find two functions $f$ and $g$ such that the composition of $f$ and $g$ gives us the function $H(x)$. The function $H(x)$ can be broken down into two parts: the inner function $5-7x$ and the outer function $x^5$. We can use these two parts to define our functions $f$ and $g$.

Step 2 ：Final Answer: \[\boxed{\begin{array}{l} f(x)=x^{5} \\ g(x)=5-7x \end{array}}\]