Problem

The number of bacteria $P(t)$ in a certain population increases according to the following function, where time $t$ is measured in hours. \[ P(t)=1700 e^{0.25 t} \] Find the number of bacteria in the population after 4 hours and after 8 hours. Round your answers to the nearest whole number as necessary. Number after 4 hours: bacteria Number after 8 hours: bacteria

Solution

Step 1 :The problem is asking for the number of bacteria after 4 hours and 8 hours. This can be found by substituting \(t=4\) and \(t=8\) into the given function \(P(t)=1700 e^{0.25 t}\) and calculating the result.

Step 2 :After substituting \(t=4\) into the function, we get \(P_4 = 1700 e^{0.25 \times 4} = 4621\) bacteria.

Step 3 :After substituting \(t=8\) into the function, we get \(P_8 = 1700 e^{0.25 \times 8} = 12561\) bacteria.

Step 4 :Final Answer: The number of bacteria in the population after 4 hours is approximately \(\boxed{4621}\) and after 8 hours is approximately \(\boxed{12561}\).

From Solvely APP
Source: https://solvelyapp.com/problems/19615/

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