\[ \tan ^{2} x-\sec ^{2} x \] chacse the carrect answer below 1 $\sec x$ $-1$ $-\cos ^{2} x$

Step 1 ：The given expression is \(\tan ^{2} x-\sec ^{2} x\).

Step 2 ：We know that \(\tan ^{2} x = \sec ^{2} x - 1\) and \(\sec ^{2} x = \tan ^{2} x + 1\).

Step 3 ：We can substitute \(\tan ^{2} x\) with \(\sec ^{2} x - 1\) in the given expression.

Step 4 ：The simplified expression is -1. This means that \(\tan ^{2} x-\sec ^{2} x = -1\).

Step 5 ：Final Answer: \(\boxed{-1}\)