Use the graph of $f(x)=\log _{3} x$ to graph the function $f(x)=\left(\log _{3} x\right)+8$. Then give the domain and range.

Step 1 ：The function \(f(x)=\left(\log _{3} x\right)+8\) is a vertical shift of the function \(f(x)=\log _{3} x\) by 8 units upwards.

Step 2 ：This means that the graph of the function \(f(x)=\left(\log _{3} x\right)+8\) will be the same as the graph of \(f(x)=\log _{3} x\), but every point will be 8 units higher.

Step 3 ：The domain of the function \(f(x)=\left(\log _{3} x\right)+8\) will be the same as the domain of \(f(x)=\log _{3} x\), which is \((0, \infty)\), because the logarithm is only defined for positive numbers.

Step 4 ：The range of the function \(f(x)=\left(\log _{3} x\right)+8\) will be \((-\infty, \infty)\), because the logarithm can take any real number value and we are shifting all those values 8 units upwards.

Step 5 ：\(\boxed{\text{Final Answer: The graph of the function } f(x)=\left(\log _{3} x\right)+8 \text{ is a vertical shift of the function } f(x)=\log _{3} x \text{ by 8 units upwards. The domain of the function is } (0, \infty) \text{ and the range is } (-\infty, \infty).}\)