A 90-horsepower outboard motor at full throttle will rotate its propeller at exactly 4100 revolutions per min. Find the angular speed of the propeller in radians per second. 4100 rev per min $\approx \square$ radians per sec (Round to the nearest tenth as needed.)

Step 1 ：We are given that the outboard motor rotates its propeller at 4100 revolutions per minute. We need to find the angular speed in radians per second.

Step 2 ：First, we convert the revolutions per minute to revolutions per second. We know that 1 minute is equal to 60 seconds. So, we divide 4100 by 60 to get the revolutions per second. This gives us approximately 68.33 revolutions per second.

Step 3 ：Next, we convert the revolutions to radians. We know that 1 revolution is equal to \(2\pi\) radians. So, we multiply 68.33 by \(2\pi\) to get the angular speed in radians per second. This gives us approximately 429.35 radians per second.

Step 4 ：Final Answer: The angular speed of the propeller in radians per second is approximately \(\boxed{429.4}\) radians per second.