Step 1 :Given that the radius of the flywheel, \(r\), is 14 cm and the angular speed, \(\omega\), is 12 radians per second.
Step 2 :The linear speed, \(v\), of a point on the rim of a rotating object is given by the formula \(v = r\omega\). Substituting the given values, we get \(v = 14 \times 12 = 168\) cm/sec.
Step 3 :We need to convert the linear speed from cm/sec to cm/min by multiplying by 60. So, \(v_{min} = 168 \times 60 = 10080\) cm/min.
Step 4 :Final Answer: The linear speed of a point on the rim of the flywheel is approximately \(\boxed{10080}\) cm/min.