A tire is rotating 720 times per min. Through how many degrees does a point on the edge of the fire move in $\frac{1}{6} \sec ?$ The point on the edge of the tire rotates in $\frac{1}{6}$ sec. (Type an integer or a simplified fraction.)

Step 1 ：Convert the rotations per minute to rotations per second: \(\frac{720}{60} = 12\) rotations per second.

Step 2 ：Calculate how much rotation happens in \(\frac{1}{6}\) of a second: \(12 \times \frac{1}{6} = 2\) rotations.

Step 3 ：Since one full rotation is 360 degrees, multiply the number of rotations by 360 to get the rotation in degrees: \(2 \times 360 = 720\) degrees.

Step 4 ：Final Answer: The point on the edge of the tire moves through \(\boxed{720}\) degrees in \(\frac{1}{6}\) sec.