Suppose $F(2)=5, F(5)=-7$, and $F^{\prime}(x)=f(x)$. \[ \int_{2}^{5} f(x) d x= \]

Step 1 ：Suppose $F(2)=5, F(5)=-7$, and $F^{\prime}(x)=f(x)$.

Step 2 ：The integral of a function from a to b is equal to the difference of the function's values at b and a, if the function is the derivative of another function. This is the Fundamental Theorem of Calculus.

Step 3 ：In this case, we are given that $f(x)$ is the derivative of $F(x)$, so we can apply this theorem to find the integral of $f(x)$ from 2 to 5.

Step 4 ：Substitute the given values into the formula: $F(5) - F(2) = -7 - 5 = -12$

Step 5 ：Final Answer: The integral of $f(x)$ from 2 to 5 is \(\boxed{-12}\).