Problem

A baseball player swings and connects with a pitch. The equation $H=-16 t^{2}+80 t+4$ represents the height of the ball (in feet) above the ground after $t$ seconds. Determine the height of the ball after 1.1 seconds. Do not round your result. The height of the ball after 1.1 seconds is

Solution

Step 1 :The problem provides the equation \(H=-16 t^{2}+80 t+4\) which represents the height of the ball (in feet) above the ground after \(t\) seconds.

Step 2 :We are asked to determine the height of the ball after 1.1 seconds. This can be found by substituting \(t=1.1\) into the equation.

Step 3 :Substituting \(t=1.1\) into the equation gives us \(H=-16*(1.1)^{2}+80*(1.1)+4\).

Step 4 :Solving the equation gives us \(H=72.64\).

Step 5 :Final Answer: The height of the ball after 1.1 seconds is \(\boxed{72.64}\) feet.

From Solvely APP
Source: https://solvelyapp.com/problems/19490/

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