Step 1 :Given that \(\sin \theta = 1\), we know that \(\theta\) is \(90^\circ\) or \(\frac{\pi}{2}\) radians.
Step 2 :Using the Pythagorean identity \(\sin^2 \theta + \cos^2 \theta = 1\), we can solve for \(\cos \theta\). Substituting \(\sin \theta = 1\) into the equation, we get \(1 + \cos^2 \theta = 1\). Solving for \(\cos \theta\), we get \(\cos \theta = 0\). So, \(\cos \theta = \boxed{0}\).
Step 3 :Next, we find \(\tan \theta\) using the identity \(\tan \theta = \frac{\sin \theta}{\cos \theta}\). Substituting \(\sin \theta = 1\) and \(\cos \theta = 0\) into the equation, we see that \(\tan \theta\) is undefined because we cannot divide by zero. So, \(\tan \theta = \text{undefined}\).
Step 4 :Next, we find \(\csc \theta\) using the identity \(\csc \theta = \frac{1}{\sin \theta}\). Substituting \(\sin \theta = 1\) into the equation, we get \(\csc \theta = 1\). So, \(\csc \theta = \boxed{1}\).
Step 5 :Finally, we find \(\sec \theta\) using the identity \(\sec \theta = \frac{1}{\cos \theta}\). Substituting \(\cos \theta = 0\) into the equation, we see that \(\sec \theta\) is undefined because we cannot divide by zero. So, \(\sec \theta = \text{undefined}\).