A tire is rotating 480 times per min. Through how many degrees does a point on the edge of the fire move in $\frac{1}{2}$ sec? The point on the edge of the tire rotates $\square^{\circ}$ in $\frac{1}{2}$ sec. (Type an integer or a simplified fraction.)

Step 1 ：The tire is rotating 480 times per minute. This means it is rotating \(480 \times 360\) degrees per minute (since one full rotation is 360 degrees).

Step 2 ：So, the total degrees rotated per minute is \(480 \times 360 = 172800\) degrees.

Step 3 ：We need to find out how many degrees it rotates in half a second. There are 60 seconds in a minute, so half a second is \(\frac{1}{120}\) of a minute.

Step 4 ：Therefore, we need to find \(\frac{1}{120}\) of the total degrees rotated per minute.

Step 5 ：So, the degrees rotated in half a second is \(\frac{1}{120} \times 172800 = 1440\) degrees.

Step 6 ：Final Answer: The point on the edge of the tire rotates \(\boxed{1440}\) degrees in \(\frac{1}{2}\) sec.