Problem

Sans Serif Ashley Kevin Lisa 1. What is the length of the crust in John's slice? 3.14159 $\times 16=50.27$ inches $360 / 8=45$ degrees $45 / 360 \times 50.265=5.029=5.03$ inches 2. What is the area of John's slice? $16 / 2=8$ inches $3.14159 \times 64=201.02$ inches $36 / 360=0.11 / 10 \times 201.06=20.11$ inches 3. What is the length of the crust in Susan's slice? $3.14159 \times 16=50.27$ $45 / 360=0.125$ $0.125 \times 50.27=6.28$ inches

Solution

Step 1 :Given that John's and Susan's slices are parts of a circular pizza with a radius of 16 inches, and each slice is a 45-degree sector of the pizza, we can calculate the length of the crust (which is the length of the arc of each sector) and the area of each slice.

Step 2 :For John's slice, the length of the crust (arc length) can be calculated using the formula: Arc length = \(\frac{\theta}{360}\) * 2\(\pi\)r, where \(\theta\) is the angle of the sector (in degrees) and r is the radius of the circle.

Step 3 :The area of the slice can be calculated using the formula: Area = \(\frac{\theta}{360}\) * \(\pi\)r², where \(\theta\) is the angle of the sector (in degrees) and r is the radius of the circle.

Step 4 :Let's calculate the length of the crust and the area of John's slice first. The radius is 16 and the angle is 45.

Step 5 :The length of the crust in John's slice is approximately \(\boxed{12.57}\) inches and the area of John's slice is approximately \(\boxed{100.53}\) square inches.

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