Step 1 :Suppose \(\theta\) is in the interval \(\left(90^{\circ}, 180^{\circ}\right)\). We need to find the sign of the following: \[\sin \left(\theta-90^{\circ}\right)\]
Step 2 :The sine function is positive in the first and second quadrants, and negative in the third and fourth quadrants.
Step 3 :Since \(\theta\) is in the interval \(\left(90^{\circ}, 180^{\circ}\right)\), \(\theta-90^{\circ}\) will be in the interval \(\left(0^{\circ}, 90^{\circ}\right)\), which is in the first quadrant.
Step 4 :Therefore, \(\sin \left(\theta-90^{\circ}\right)\) should be positive.
Step 5 :Final Answer: The sign of \(\sin \left(\theta-90^{\circ}\right)\) is \(\boxed{Positive}\).