Sans Serif $=14 \mathrm{px} \quad=1.5 \mathrm{pt}=\mathrm{B} I \underline{\mathrm{U}} S \underline{\mathrm{A}}$ $14-$ 1. What is the length of the crust in John's slice? \[ \begin{array}{l} 3.14159 \times 16=50.27 \text { inches } \\ 360 / 8=45 \text { degrees } \\ 45 / 360 \times 50.265=5.029=5.03 \text { inches } \end{array} \] 2. What is the area of John's slice? $16 / 2=8$ inches $3.14159 \times 64=201.02$ inches $36 / 360=0.11 / 10 \times 201.06=20.11$ inches 3. What is the length of the crust in Susan's slice?

Step 1 ：The pizza is assumed to be a perfect circle with a radius of 16 inches.

Step 2 ：The slice John has is 1/8th of the pizza, or 45 degrees of the circle.

Step 3 ：The circumference of the circle is given by the formula \(2 \pi \times \text{radius}\).

Step 4 ：The length of the crust on John's slice would be 1/8th of the total circumference.

Step 5 ：Calculate the circumference: \(2 \pi \times 16 = 100.53\) inches.

Step 6 ：Calculate the length of the crust: \(\frac{1}{8} \times 100.53 = 12.57\) inches.

Step 7 ：Final Answer: The length of the crust in John's slice is approximately \(\boxed{12.57}\) inches.