Step 1 :The claim is that the population mean, \(\mu\), is not equal to 7000. The level of significance is \(\alpha = 0.02\). The sample statistics are: sample mean \(\bar{x} = 6600\), sample size \(n = 44\), and standard deviation \(\sigma = 369\).
Step 2 :The null hypothesis, \(H_0\), is the statement that the parameter takes the value specified in the claim. The alternative hypothesis, \(H_a\), is the statement that the parameter takes a value that contradicts the claim.
Step 3 :In this case, the null hypothesis is \(H_0: \mu = 7000\) and the alternative hypothesis is \(H_a: \mu \neq 7000\).
Step 4 :The standardized test statistic for a hypothesis test of a population mean is a z-score (z). The z-score is calculated by subtracting the population mean from the sample mean, and then dividing by the standard deviation divided by the square root of the sample size.
Step 5 :Using the given values, the z-score is calculated as follows: \(z = \frac{\bar{x} - \mu}{\sigma / \sqrt{n}}\). Substituting the given values, we get \(z = \frac{6600 - 7000}{369 / \sqrt{44}}\).
Step 6 :The calculated z-score is -7.19. This value is the standardized test statistic. It represents how many standard deviations the sample mean is away from the population mean under the null hypothesis.
Step 7 :Final Answer: The standardized test statistic is \(\boxed{-7.19}\).