Problem

State whether the following statement is true or false The center of the circle $(x+3)^{2}+(y-2)^{2}=13$ is $(3,-2)$

Solution

Step 1 :The center of a circle in the standard form \((x-h)^2 + (y-k)^2 = r^2\) is given by the point \((h, k)\).

Step 2 :The given equation of the circle is \((x+3)^2 + (y-2)^2 = 13\).

Step 3 :By comparing this with the standard form, we find that \(h = -3\) and \(k = 2\).

Step 4 :The given point is \((3, -2)\).

Step 5 :Therefore, the statement 'The center of the circle \((x+3)^{2}+(y-2)^{2}=13\) is \((3,-2)\)' is False.

Step 6 :The actual center of the circle is \((-3,2)\).

Step 7 :Final Answer: \(\boxed{\text{The statement is False. The center of the circle is } (-3,2)}\)

From Solvely APP
Source: https://solvelyapp.com/problems/19138/

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