Problem

Use the following information to answer the next question LEGEND: \[ \begin{array}{l} a=8 m \\ b=3 m \end{array} \] 14. Determine the surface area of the right cone shown, to the nearest square metre, assuming the cone is closed. $70 m^{2}$ $98 m^{2}$ $81 m^{2}$ $109 \mathrm{~m}^{2}$

Solution

Step 1 :Given that the height (a) of the cone is 8m and the radius (b) is 3m.

Step 2 :The formula for the surface area of a cone is \(\pi r(r + \sqrt{h^2 + r^2})\), where r is the radius and h is the height.

Step 3 :Substitute the given values into the formula: \(\pi * 3(3 + \sqrt{8^2 + 3^2})\).

Step 4 :Calculate the surface area to get approximately 108.8 square meters.

Step 5 :Round this value to the nearest whole number to get 109 square meters.

Step 6 :Final Answer: The surface area of the right cone, to the nearest square meter, is \(\boxed{109}\) square meters.

From Solvely APP
Source: https://solvelyapp.com/problems/19076/

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