Step 1 :Let the initial score be \(A_1\) and the common difference between the scores be \(d\). Then, \(A_1 = 58, A_2 = 58 + d = 63, A_3 = 58 + 2d = 68\).
Step 2 :Find the common difference, \(d = A_2 - A_1 = 63 - 58 = 5\).
Step 3 :Then, find the assessment at which she scores above 85: \(A_n > 85\), where \(A_n = A_1 + (n - 1)d\). Substitute values: \(A_n = 58 + (n - 1)5 > 85\).
Step 4 :Solve for \(n\): \(n > 6.4\). So, we find assessments 7, 8, and 9.