Step 1 :Given that the researcher wishes to estimate the population proportion of adults who support labeling legislation for genetically modified organisms (GMOs) with a 95% confidence level and a margin of error of 3%, we can use the formula for the sample size of a proportion to find the minimum sample size needed.
Step 2 :The formula for the sample size of a proportion is \(n = \frac{Z^2 * p * (1-p)}{E^2}\), where n is the sample size, Z is the z-score for the desired confidence level, p is the estimated proportion, and E is the desired margin of error.
Step 3 :For a 95% confidence level, the z-score (Z) is 1.96. The desired margin of error (E) is 3%, or 0.03.
Step 4 :For part (a), since no preliminary estimate is available, we use p = 0.5. Substituting these values into the formula, we get \(n = \frac{(1.96)^2 * 0.5 * (1-0.5)}{(0.03)^2}\), which simplifies to n = 1068.
Step 5 :For part (b), we use the estimate from the prior study, p = 0.78. Substituting these values into the formula, we get \(n = \frac{(1.96)^2 * 0.78 * (1-0.78)}{(0.03)^2}\), which simplifies to n = 733.
Step 6 :Comparing the results from parts (a) and (b), we can see that the minimum sample size needed is larger when no prior information is available.
Step 7 :Final Answer: The minimum sample size needed assuming that no prior information is available is \(\boxed{1068}\). The minimum sample size needed using a prior study that found that 78% of the respondents support labeling legislation is \(\boxed{733}\).