Find the horizontal asymptote of the given function. \[ g(x)=\frac{x^{2}+8 x-8}{x-8} \] A. $y=-8$ B. $y=8$ C. $y=0$ D. None

Step 1 ：Find the horizontal asymptote of the given function. \[g(x)=\frac{x^{2}+8 x-8}{x-8}\]

Step 2 ：The horizontal asymptote of a rational function can be found by comparing the degrees of the numerator and denominator.

Step 3 ：If the degree of the numerator is less than the degree of the denominator, the horizontal asymptote is y=0.

Step 4 ：If the degrees are equal, the horizontal asymptote is the ratio of the leading coefficients.

Step 5 ：If the degree of the numerator is greater than the degree of the denominator, there is no horizontal asymptote.

Step 6 ：In this case, the degree of the numerator is 2 and the degree of the denominator is 1.

Step 7 ：Therefore, there is no horizontal asymptote.

Step 8 ：Final Answer: \(\boxed{\text{D. None}}\)