Find a polynomial of degree 3 with real coefficients and zeros of $-3,-1$, and 4 , for which $f(-2)=-30$. Simplify, do not factor.

Step 1 ：We start by writing the polynomial of degree 3 with zeros at -3, -1, and 4 in the form \(f(x) = a(x+3)(x+1)(x-4)\) for some real number a.

Step 2 ：We can find the value of a by substituting x=-2 into the equation and setting it equal to -30. This gives us \(a = -5\).

Step 3 ：Substituting the value of a back into the polynomial, we get the final polynomial \(f(x) = -5(x+3)(x+1)(x-4)\).

Step 4 ：Thus, the polynomial of degree 3 with real coefficients and zeros of -3, -1, and 4, for which \(f(-2)=-30\) is \(\boxed{-5(x+3)(x+1)(x-4)}\).