Find a polynomial of degree 3 with real coefficients and zeros of $-3,-1$, and 4 , for which $f(-2)=-30$.

Step 1 ：The polynomial of degree 3 with zeros at -3,-1, and 4 can be written in the form \(f(x) = a(x+3)(x+1)(x-4)\) for some real number \(a\).

Step 2 ：We can find the value of \(a\) by substituting \(x=-2\) into the equation and setting it equal to \(-30\).

Step 3 ：Solving for \(a\), we find that \(a = -5\).

Step 4 ：Substituting \(a = -5\) back into the equation, we get the polynomial \(f(x) = -5(x+3)(x+1)(x-4)\).

Step 5 ：Final Answer: The polynomial of degree 3 with real coefficients and zeros of -3,-1, and 4 , for which \(f(-2)=-30\) is \(\boxed{-5(x+3)(x+1)(x-4)}\).