Problem

$\frac{2-(-3)^{2}-1}{(1-3)^{2}}$

Solution

Step 1 :Given the expression \(\frac{2-(-3)^{2}-1}{(1-3)^{2}}\)

Step 2 :According to the order of operations, we first calculate the exponentiation, which gives us \(\frac{2-9-1}{(1-3)^{2}}\)

Step 3 :Next, we perform the subtraction inside the parentheses, which gives us \(\frac{2-9-1}{(-2)^{2}}\)

Step 4 :Then, we perform the exponentiation, which gives us \(\frac{2-9-1}{4}\)

Step 5 :Next, we perform the subtraction in the numerator, which gives us \(\frac{-8}{4}\)

Step 6 :Finally, we perform the division, which gives us -2.0

Step 7 :So, the simplified form of the given expression is \(\boxed{-2.0}\)

From Solvely APP
Source: https://solvelyapp.com/problems/18797/

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