Step 1 :Given the quadratic equation \(2x^{2}-28x+98=0\).
Step 2 :Identify the coefficients as \(a = 2\), \(b = -28\), and \(c = 98\).
Step 3 :Use the quadratic formula to solve for \(x\), which is \(x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}\).
Step 4 :Substitute the values of \(a\), \(b\), and \(c\) into the formula.
Step 5 :Calculate the discriminant \(D = b^{2}-4ac\). In this case, \(D = 0\).
Step 6 :Since the discriminant is zero, the equation has a repeated root.
Step 7 :Calculate the roots \(x1 = \frac{-b + \sqrt{D}}{2a} = 7.0\) and \(x2 = \frac{-b - \sqrt{D}}{2a} = 7.0\).
Step 8 :Final Answer: The solution to the equation is \(\boxed{7}\).