Problem

(a) Find an angle $\theta$, with $0^{\circ}<\theta<360^{\circ}$, that has the same cosine as $65^{\circ}$ (but is not $65^{\circ}$ ). (b) Find an angle $\theta$, with $0^{\circ}<\theta<360^{\circ}$, that has the same sine as $65^{\circ}$ (but is not $65^{\circ}$ ).

Solution

Step 1 :For part (a), we know that cosine is positive in both the first and fourth quadrants. So, the angle that has the same cosine as \(65^{\circ}\) would be in the fourth quadrant and can be found by subtracting \(65^{\circ}\) from \(360^{\circ}\).

Step 2 :For part (b), sine is positive in the first and second quadrants. So, the angle that has the same sine as \(65^{\circ}\) would be in the second quadrant and can be found by subtracting \(65^{\circ}\) from \(180^{\circ}\).

Step 3 :The angle that has the same cosine as \(65^{\circ}\) is \(\boxed{295^{\circ}}\) and the angle that has the same sine as \(65^{\circ}\) is \(\boxed{115^{\circ}}\).

From Solvely APP
Source: https://solvelyapp.com/problems/18715/

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