Through (4,1) ; slope 3

Step 1 ：Given a point (4,1) and a slope of 3, we can substitute these values into the general form of a linear equation y = mx + b.

Step 2 ：Substituting x = 4, y = 1, and m = 3, we get 1 = 3*4 + b.

Step 3 ：Solving for b, we get b = -11.

Step 4 ：Substituting m = 3 and b = -11 into the equation y = mx + b, we get the final equation of the line: \(\boxed{y = 3x - 11}\).