Simplify $\sin ^{2} x+\sin ^{2} x \cot ^{2} x$

Step 1 ：Rewrite the given expression as \(\sin ^{2} x+\sin ^{2} x \frac{\cos ^{2} x}{\sin ^{2} x}\)

Step 2 ：Cancel out the \(\sin ^{2} x\) in the denominator and numerator, leaving us with \(\sin ^{2} x + \cos ^{2} x\)

Step 3 ：According to the Pythagorean identity, \(\sin ^{2} x + \cos ^{2} x = 1\)

Step 4 ：So, the simplified form of the given expression is \(\boxed{1}\)