\begin{tabular}{|r|r|r|r|r|} \hline & A & B & C & Total \\ \hline Male & 12 & 15 & 8 & 35 \\ \hline Female & 18 & 7 & 10 & 35 \\ \hline Total & 30 & 22 & 18 & 70 \\ \hline \end{tabular} If one student is chosen at random, Find the probability that the student was male OR got an " $A$ ". Submit Question

Step 1 ：Given the table, we can see that the total number of students is 70.

Step 2 ：The number of male students is 35 and the number of students who got an 'A' is 30.

Step 3 ：However, we have counted the male students who got an 'A' twice. This group has 12 students.

Step 4 ：To find the number of students who are either male or got an 'A', we add the number of male students and the number of students who got an 'A', and then subtract the number of male students who got an 'A'. This gives us \(35 + 30 - 12 = 53\).

Step 5 ：The probability of an event can be calculated by dividing the number of ways the event can occur by the total number of outcomes. In this case, the event is that the student is male or got an 'A'.

Step 6 ：So, the probability that the student was male or got an 'A' is \(\frac{53}{70} = 0.7571428571428571\).

Step 7 ：Final Answer: The probability that the student was male or got an 'A' is approximately \(\boxed{0.757}\).