Consider the following binomial experiment: According to a survey, $64 \%$ of adult Americans operate the flusher of toilets in public restrooms with their foot. Suppose a random sample of $n=20$ adult Americans is obtained and the number who flush public toilets with their foot is recorded. What is the probability that at least 15 flush public toilets with their foot? [Select]

Step 1 ：We are given a binomial distribution problem. The binomial distribution model is appropriate for a statistical experiment if the following conditions are met:

Step 2 ：1. The experiment consists of n repeated trials.

Step 3 ：2. Each trial can result in just two possible outcomes. We call one of these outcomes a success and the other, a failure.

Step 4 ：3. The probability of success, denoted by P, is the same on every trial.

Step 5 ：4. The trials are independent; that is, the outcome on one trial does not affect the outcome on other trials.

Step 6 ：In this case, we have \(n=20\) trials (the 20 adult Americans), each trial can result in two outcomes (either they flush with their foot or they don't), the probability of success (flushing with foot) is 0.64, and we can assume the trials are independent (one person flushing with their foot doesn't affect whether another person will).

Step 7 ：We want to find the probability that at least 15 out of 20 flush with their foot. This is equivalent to finding the probability of exactly 15, 16, 17, 18, 19, and 20 successes, and then adding those probabilities together.

Step 8 ：Using the given values, \(n = 20\) and \(p = 0.64\), we calculate the probability to be approximately 0.217.

Step 9 ：Final Answer: The probability that at least 15 out of 20 adult Americans flush public toilets with their foot is approximately \(\boxed{0.217}\).