A survey found that $64 \%$ of adult Americans operates the flusher of toilets in public restrooms with their foot. Suppose a random sample of $n=500$ adult Americans is obtained and the number who flush public toilets with their foot is recorded. Find the shape of the binomial probability distribution. Since $n p(1-p)=$ the shape is

Step 1 ：Given that the number of trials, denoted as n, is 500 and the probability of success, denoted as p, is 0.64.

Step 2 ：The mean of a binomial distribution is given by np. Substituting the given values, we get \(500 \times 0.64 = 320\).

Step 3 ：The variance of a binomial distribution is given by np(1-p). Substituting the given values, we get \(500 \times 0.64 \times (1-0.64) = 115.2\).

Step 4 ：The mean and variance of the binomial distribution are 320 and 115.2 respectively.

Step 5 ：This suggests that the distribution is unimodal (has one peak) and is skewed to the right, since the mean is greater than the median in a binomial distribution.

Step 6 ：\(\boxed{\text{The shape of the binomial probability distribution is unimodal and skewed to the right.}}\)