Find the equation of the line using the point-slope formula. Write the final equation using the slope-intercept form. $(x, y)=(-3,10)$ and $(x, y)=(2,-5)$ are points on the line

Step 1 ：Given points are (-3,10) and (2,-5).

Step 2 ：Calculate the slope (m) using the formula \(m = \frac{y_2 - y_1}{x_2 - x_1}\). Substituting the given points, we get \(m = \frac{-5 - 10}{2 - (-3)} = -3.0\).

Step 3 ：Substitute the slope and one of the points into the point-slope formula \(y - y_1 = m(x - x_1)\) to find the equation of the line. Using point (-3,10) and slope -3.0, we get \(y - 10 = -3.0(x - (-3))\).

Step 4 ：Simplify the equation to get it in slope-intercept form \(y = mx + b\). After simplification, we get \(y = -3.0x + 1.0\).

Step 5 ：Final Answer: The equation of the line is \(\boxed{y = -3.0x + 1.0}\).