Step 1 :The problem is asking for the probability of selecting two solid chocolates in a row. The probability of an event is calculated by dividing the number of ways the event can occur by the total number of outcomes.
Step 2 :In this case, the total number of outcomes is the total number of chocolates, which is 32. The number of ways to select a solid chocolate is 9 (since there are 9 solid chocolates).
Step 3 :So, the probability of selecting a solid chocolate on the first pick is \(\frac{9}{32}\).
Step 4 :After eating one solid chocolate, there are now 31 chocolates left, 8 of which are solid. So, the probability of selecting a solid chocolate on the second pick is \(\frac{8}{31}\).
Step 5 :The probability of both events happening (i.e., selecting a solid chocolate on the first pick AND selecting a solid chocolate on the second pick) is the product of the probabilities of each event.
Step 6 :Final Answer: The probability of selecting 2 solid chocolates in a row is \(\boxed{0.0726}\) or \(\boxed{7.26\%}\).