Use a system of linear equations with two variables and two equations to solve. CDs. cast. $\$ 2.95$.more than DVDs at All Bets Are Off Electronics. How much would 6 CDs and 2 DVDs cost if 5 CDs and 2 DVDs cost \$119.68?

Step 1 ：Let's denote the cost of a CD as C and the cost of a DVD as D.

Step 2 ：From the problem, we know that a CD costs $2.95 more than a DVD. We can write this as an equation: \(C = D + 2.95\).

Step 3 ：We also know that 5 CDs and 2 DVDs cost $119.68. We can write this as another equation: \(5C + 2D = 119.68\).

Step 4 ：We can solve this system of equations to find the values of C and D.

Step 5 ：The solution to the system of equations is \(C = 17.94\) and \(D = 14.99\).

Step 6 ：We can then use these values to find the cost of 6 CDs and 2 DVDs: \(6C + 2D\).

Step 7 ：Substituting the values of C and D, we get the cost as $137.62.

Step 8 ：\(\boxed{The cost of 6 CDs and 2 DVDs is $137.62}\)