Use the logistic growth model $f(x)=\frac{130}{1+5 e^{-2 x}}$. Find the carrying capacity.

Step 1 ：Use the logistic growth model \(f(x)=\frac{130}{1+5 e^{-2 x}}\). Find the carrying capacity.

Step 2 ：The carrying capacity in a logistic growth model is the maximum value that the function can reach.

Step 3 ：In the given logistic growth model \(f(x)=\frac{130}{1+5 e^{-2 x}}\), the carrying capacity is the value of the function as \(x\) approaches infinity.

Step 4 ：This is because as \(x\) gets larger and larger, the exponential term \(e^{-2x}\) gets closer and closer to zero, and the function approaches its maximum value.

Step 5 ：Therefore, the carrying capacity is the coefficient of the numerator, which is 130 in this case.

Step 6 ：Final Answer: The carrying capacity of the logistic growth model \(f(x)=\frac{130}{1+5 e^{-2 x}}\) is \(\boxed{130}\).